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<p>[QUOTE=&quot;fatima, post: 1169266, member: 22143&quot;]Interesting the COA doesn&#039;t give the weight.&nbsp;&nbsp; However mathematically computing from what they did provide, this proof looks to be ~(2.59&quot; x 6.10&quot;).&nbsp; No thickness is specified.&nbsp;&nbsp; If you assume the same thickness as a ASE of 0.12&quot;, then you have an object that has a volume of ~1.9 cubic inches.&nbsp; (lots of rounding)&nbsp;&nbsp; This is 31.13 cc.&nbsp; Density of pure silver is 10.49g per cc.&nbsp; So given these assumptions this is 327 grams or 10.5 troy ounces of silver.&nbsp;&nbsp; </p><p><br /></p><p>(not the most efficient way to calculate this, but I wanted to eliminate error)</p><p><br /></p><p><u>So most likely, it&#039;s close to 10 ounces</u> assuming I didn&#039;t make a math mistake and just a little thinner than a ASE.&nbsp; Of course it could be a whole lot thinner but this will give you an idea of its geometry.</p><p><br /></p><p>Now the question of the say is if &quot;struck&quot; in .999 silver means that it is actually .999 silver, or an amalgamation of silver and something else.&nbsp;&nbsp; If the actual weight of silver is not stamped on the proof, I&#039;d probably be afraid of it.[/QUOTE]</p><p><br /></p>

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