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Why is machine doubling not worth much?
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<p>[QUOTE="Drusus, post: 828318, member: 6370"]Not at all...</p><p> </p><p>If you have 5 dies, 4 have no errors, and one does, you have this:</p><p> </p><p>Die 1. Error = 1,000,000</p><p>Die 2. No Error = 1,000,000</p><p>Die 3. No Error = 1,000,000</p><p>Die 4. No Error = 1,000,000</p><p>Die 5. No Error = 1,000,000</p><p> </p><p>So out of 5,000,000 coins you have roughly 4,000,000 without error and roughly identical and a just 1,000,000 with the error. That makes the error 1 in a million and the non-error 1 in 4 million. If 1 billion coins are produced and there is only one die with the error then the error is one in a million errors out of a billion total coins produced while the non-error coins would be one in 999,000,000</p><p> </p><p>this is not taking into consideration the error not being caught and them producing far less.</p><p> </p><p>to me the machine doubling is often the more unique error, there are more of them but each on seems to me at least slightly different than the next[/QUOTE]</p><p><br /></p>
[QUOTE="Drusus, post: 828318, member: 6370"]Not at all... If you have 5 dies, 4 have no errors, and one does, you have this: Die 1. Error = 1,000,000 Die 2. No Error = 1,000,000 Die 3. No Error = 1,000,000 Die 4. No Error = 1,000,000 Die 5. No Error = 1,000,000 So out of 5,000,000 coins you have roughly 4,000,000 without error and roughly identical and a just 1,000,000 with the error. That makes the error 1 in a million and the non-error 1 in 4 million. If 1 billion coins are produced and there is only one die with the error then the error is one in a million errors out of a billion total coins produced while the non-error coins would be one in 999,000,000 this is not taking into consideration the error not being caught and them producing far less. to me the machine doubling is often the more unique error, there are more of them but each on seems to me at least slightly different than the next[/QUOTE]
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Why is machine doubling not worth much?
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