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<p>[QUOTE=&quot;desertgem, post: 772929, member: 15199&quot;]<p style="text-align: left"><span style="color: #000000"></span></p> <p style="text-align: left"><span style="color: #000000"><br /></span></p> <p style="text-align: left"><span style="color: #000000">In the absorption model, imagine various photons bearing energy levels that produce various wavelengths of color hitting the surface( photons can be particles or waves. If the chemical structure of the silver sulfide or other toning agent causes the absorption ( incorporation into the chemical structure), then the remaining photons of different energy levels (color) can be reflected from the&nbsp; surface layer of the sulfide,oxide, whatever the toning agent is, so the apparent color will be all colors minus the color absorbed, angle of viewing would have limited effect on the tone color since the surface layer of the toning chemical would not have a &quot;mirror&quot; surface and the scattering would allow the similar proportions of remaining color to hit the retina and the brain interpret the same color.</span></p> <p style="text-align: left"><span style="color: #000000"><br /></span></p> <p style="text-align: left"><span style="color: #000000">When looking at photons as waves, we can see the wave actions where waves can cancel out, increase positive waveform or increase negative waveform, depening on how much out of phase the waveforms happen to be. The one reference shows how the phase is altered by the thickness of the thin film of toning material. This is how the different preceived ( by the eye/mind) colors are visualized. As the thickness increases, the phase difference doesn&#039;t just increase, it cycles ( + 0 - , + 0 -, etc) until the layer is so thick the reflectance is negated ( black end point). For one set of photons, the color would be very directional. However, the surface they are reflecting off is also not a &quot;mirror&quot; surface ( coin surface), so tilting the coin may direct other photons with similar phase difference into the eye and the same color in the same area.</span></p> <p style="text-align: left"><span style="color: #000000"><br /></span></p> <p style="text-align: left"><span style="color: #000000">This the understanding I have on the processes, maybe others can add or correct.</span></p> <p style="text-align: left"><span style="color: #000000"><br /></span></p> <p style="text-align: left"><span style="color: #000000">Jim</span></p> <p style="text-align: left"><span style="color: #000000"><br /></span></p> <p style="text-align: left"><span style="color: #000000"><br /></span></p><p>[/QUOTE]</p><p><br /></p>

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