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<p>[QUOTE=&quot;Burton Strauss III, post: 2852052, member: 59677&quot;]You are correct...</p><p><br /></p><p><br /></p><p>Per the Mint&#039;s specifications, the cent is 19.05mm in diameter (9.525mm radius) and 1.52mm thick (height) at the rim.</p><p><br /></p><p>It&#039;s never that simple</p><p><br /></p><p>The alloy is 97.5% Zn and 2.5% Cu.</p><ul> <li>Zinc has a density of 7.0861 g/cm^3</li> <li>Copper has a density of 8.9286 g/cm^3</li> </ul><p>An alloy of 97.5% Zn / 2.5% Cu (by mass) would have a density of 8.8808 g/cm^3. And a cylinder of 19.05mm x 1.52mm would weigh 3.847g.</p><p><br /></p><p>BUT the mint specification is 3.11gm (and we know most of the coin does not reach the height of the rim or it would not stack).</p><p><br /></p><p>Simple math gives us 3.11/3.847 is 80.83% or an AVERAGE (height) of 1.229mm.</p><p><br /></p><p>Then applying the volume of the cylinder formula (v = Pi * r^2 * h) gives us the volume of 350.3 mm^3</p><p><br /></p><p>The volume of the zinc core is that of a cylinder 20 microns smaller (9.505mm x 1.189mm - you subtract 20 microns from the radius, but 2x 20 microns from the height) gives 337.5 mm^3 and a weight of 3.00g.</p><p><br /></p><p>The volume of the plating is the subtraction of the two: 350.3 - 337.5 = 12.8 mm^3 or 0.11g.</p><p><br /></p><p>So the 20 micron thickness is basically proven.[/QUOTE]</p><p><br /></p>

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