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<p>[QUOTE=&quot;NSP, post: 2788527, member: 74849&quot;]Out of boredom I decided to calculate a formula for resistance if you put the leads directly across from each other on the edge of the coin (e.g.- 12 o&#039;clock and 6 o&#039;clock positions). It certainly did get very calculusy and there was even an inverse hyperbolic sine that appeared at the end, but the result was surprisingly simple. I ended up with R = 0.88137ρ/t, where ρ = resistivity and t = the thickness of the coin. </p><p><br /></p><p>The units cancel properly and I double checked my math, so I think I did it correctly. I was surprised that the resistance was completely independent of the coin&#039;s diameter, but I suppose since the length (L) and cross sectional area (A) in the R=ρL/A formula are both dependent on diameter that the diameter terms canceled out. </p><p><br /></p><p>Math is weird, especially when you use it to unnecessarily complicate coin collecting. <img src="styles/default/xenforo/clear.png" class="mceSmilieSprite mceSmilie98" alt=":wacky:" unselectable="on" unselectable="on" /></p><p><br /></p><p>[ATTACH=full]647115[/ATTACH][/QUOTE]</p><p><br /></p>

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