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<p>[QUOTE=&quot;funkee, post: 1872512, member: 37925&quot;]You did a combination calculation. We are looking for permutations, because order matters. With a combination, 12345678 is&nbsp; indistinguishable from 85647213. So there are 45 separate combinations of 8 numbers if we don&#039;t consider the order. In our case, we have many more results, because a different order means a different note.</p><p><br /></p><p>The correct formula is n! / (n-r)! = 10! / (10-8)! =</p><p><br /></p><p>(10x9x8x7x6x5x4x3x2x1) / 2x1 =</p><p><br /></p><p>10x9x8x7x6x5x4x3&nbsp; =</p><p><br /></p><p>1,814,400 notes per block. That is of course if we factor in high serial numbers that are presently reserved for sheets.</p><p><br /></p><p>P.S. Thank you for the wonderful flashback to high school math.[/QUOTE]</p><p><br /></p>

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