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I need help for a friend who got scam by a coin shop
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<p>[QUOTE="Blaubart, post: 1667910, member: 37498"]Or $44.44 each, which would be the actual price if she bought 9 rolls of 20 halves for $8000.</p><p><br /></p><p>A standard roll of half dollars = 20 coins. 8000/(20*9) = $44.44 each</p><p>If there were 25 coins in each roll, that would be: 8000/(25*9) = $35.55 each</p><p>If there were 30 coins in each roll, that would be: 8000/(30*9) = $29.69 each</p><p><br /></p><p>To get around $32 each, there would have to be 27-28 coins in each roll, which would be quite odd.</p><p><br /></p><p>Or maybe she actually bought ten rolls? Ten rolls of 20 halves with a total price of $8000 would be $40 each. But, if she bought ten rolls with 25 coins in each, then that would work out to the elusive $32 each.</p><p><br /></p><p>Either way, I'm very curious how this whole thing will turn out. Keep us informed! :thumb:[/QUOTE]</p><p><br /></p>
[QUOTE="Blaubart, post: 1667910, member: 37498"]Or $44.44 each, which would be the actual price if she bought 9 rolls of 20 halves for $8000. A standard roll of half dollars = 20 coins. 8000/(20*9) = $44.44 each If there were 25 coins in each roll, that would be: 8000/(25*9) = $35.55 each If there were 30 coins in each roll, that would be: 8000/(30*9) = $29.69 each To get around $32 each, there would have to be 27-28 coins in each roll, which would be quite odd. Or maybe she actually bought ten rolls? Ten rolls of 20 halves with a total price of $8000 would be $40 each. But, if she bought ten rolls with 25 coins in each, then that would work out to the elusive $32 each. Either way, I'm very curious how this whole thing will turn out. Keep us informed! :thumb:[/QUOTE]
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