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<p>[QUOTE="Kentucky, post: 1489493, member: 33176"]<font size="3"><font face="Times New Roman"><span style="color: #000000">OK, math time, someone check me: </span></font></font></p><p><font face="Times New Roman"><font size="3"><span style="color: #000000">Silver dollar diameter = 38.1mm = 3.81cm</span></font></font></p><p><font face="Times New Roman"><font size="3"><span style="color: #000000">Radius = 1.905cm</span></font></font></p><p><span style="color: #000000"><font face="Times New Roman"><font size="3">Face Area = </font></font><font face="Euclid Symbol"><font face="Euclid Symbol">p</font></font><font face="Times New Roman"><font size="3">r[SUP]2[/SUP] = 11.40 cm[SUP]2[/SUP]</font><font size="3"> X 2 for 2 sides = 22.80 cm</font></font>[SUP]<font face="Times New Roman"><font size="3">2</font></font>[/SUP]</span></p><p><span style="color: #000000"><font face="Times New Roman"><font size="3">Circumference = </font></font><font face="Euclid Symbol"><font face="Euclid Symbol">p</font></font><font face="Times New Roman"><font size="3">d = 11.97 cm</font></font></span></p><p><font face="Times New Roman"><font size="3"><span style="color: #000000">Thickness = 2.58 mm = 0.258 cm</span></font></font></p><p><font size="3"><span style="color: #000000"><font face="Times New Roman">Area of edge = 11.97 cm X 0.258 cm = 3.09 cm[SUP]2[/SUP]</font></span></font></p><p><font size="3"><span style="color: #000000"><font face="Times New Roman">Total area = 25.89 cm[SUP]2[/SUP]</font></span></font></p><p><font face="Times New Roman"><font size="3"><span style="color: #000000">Thickness of an Ag atom = 144 pm = 144 X 10[SUP]-12[/SUP] m = 144 X 10[SUP]-10[/SUP] cm = 1.44 X 10[SUP]-8[/SUP] cm</span></font></font></p><p><font face="Times New Roman"><font size="3"><span style="color: #000000">Assume we go 100 atoms deep for 1.44 X 10[SUP]-6[/SUP] cm</span></font></font></p><p><font size="3"><span style="color: #000000"><font face="Times New Roman">So: (1.44 X 10[SUP]-6[/SUP] cm)( 25.89 cm[SUP]2[/SUP]) = 0.000037 cm[SUP]3[/SUP]</font></span></font></p><p><font face="Times New Roman"><font size="3"><span style="color: #000000">At a density of 10.49 g/ cm[SUP]3[/SUP] this would be 0.0004 g</span></font></font></p><p><font face="Times New Roman"><font size="3"><span style="color: #000000">Measureable, but just barely so, and this is removing 100 atoms uniformly and assuming they are all touching.</span></font></font>[/QUOTE]</p><p><br /></p>
[QUOTE="Kentucky, post: 1489493, member: 33176"][SIZE=3][FONT=Times New Roman][COLOR=#000000]OK, math time, someone check me: [/COLOR][/FONT][/SIZE] [FONT=Times New Roman][SIZE=3][COLOR=#000000]Silver dollar diameter = 38.1mm = 3.81cm[/COLOR][/SIZE][/FONT] [FONT=Times New Roman][SIZE=3][COLOR=#000000]Radius = 1.905cm[/COLOR][/SIZE][/FONT] [COLOR=#000000][FONT=Times New Roman][SIZE=3]Face Area = [/SIZE][/FONT][FONT=Euclid Symbol][FONT=Euclid Symbol]p[/FONT][/FONT][FONT=Times New Roman][SIZE=3]r[SUP]2[/SUP] = 11.40 cm[SUP]2[/SUP][/SIZE][SIZE=3] X 2 for 2 sides = 22.80 cm[/SIZE][/FONT][SUP][FONT=Times New Roman][SIZE=3]2[/SIZE][/FONT][/SUP][/COLOR] [COLOR=#000000][FONT=Times New Roman][SIZE=3]Circumference = [/SIZE][/FONT][FONT=Euclid Symbol][FONT=Euclid Symbol]p[/FONT][/FONT][FONT=Times New Roman][SIZE=3]d = 11.97 cm[/SIZE][/FONT][/COLOR] [FONT=Times New Roman][SIZE=3][COLOR=#000000]Thickness = 2.58 mm = 0.258 cm[/COLOR][/SIZE][/FONT] [SIZE=3][COLOR=#000000][FONT=Times New Roman]Area of edge = 11.97 cm X 0.258 cm = 3.09 cm[SUP]2[/SUP][/FONT][/COLOR][/SIZE] [SIZE=3][COLOR=#000000][FONT=Times New Roman]Total area = 25.89 cm[SUP]2[/SUP][/FONT][/COLOR][/SIZE] [FONT=Times New Roman][SIZE=3][COLOR=#000000]Thickness of an Ag atom = 144 pm = 144 X 10[SUP]-12[/SUP] m = 144 X 10[SUP]-10[/SUP] cm = 1.44 X 10[SUP]-8[/SUP] cm[/COLOR][/SIZE][/FONT] [FONT=Times New Roman][SIZE=3][COLOR=#000000]Assume we go 100 atoms deep for 1.44 X 10[SUP]-6[/SUP] cm[/COLOR][/SIZE][/FONT] [SIZE=3][COLOR=#000000][FONT=Times New Roman]So: (1.44 X 10[SUP]-6[/SUP] cm)( 25.89 cm[SUP]2[/SUP]) = 0.000037 cm[SUP]3[/SUP][/FONT][/COLOR][/SIZE] [FONT=Times New Roman][SIZE=3][COLOR=#000000]At a density of 10.49 g/ cm[SUP]3[/SUP] this would be 0.0004 g[/COLOR][/SIZE][/FONT] [FONT=Times New Roman][SIZE=3][COLOR=#000000]Measureable, but just barely so, and this is removing 100 atoms uniformly and assuming they are all touching.[/COLOR][/SIZE][/FONT][/QUOTE]
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