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<p>[QUOTE=&quot;redparrots, post: 2962183, member: 92391&quot;]Hi Everyone, May be this question been answered many times, but I am not able to find a clear answer on this topic, so hopefully the experts in this forum can clarify this for me and thank you in advance for all replies.</p><p><br /></p><p>From what I can gather, the $50 American Gold Eagle coin composition is 91.67% gold, 3% Silver, and 5.33% Copper.&nbsp; Because of these composition, it is also known to be a 22K gold coin (this is the source of confusion to me, as far as I know 22K gold should be cheaper than 24K gold.&nbsp; The market gold spot price is base on 1 troy oz of 24K gold and not 22K gold).&nbsp; However, the coin&#039;s total weight is 1.0909oz.&nbsp; So in theory if I were to melt it and extract out just the gold, would the gold content equals to 1 Troy oz of .9999 (24K)?? </p><p>I think the answer is yes, but I need confirmation from expert on this forum.</p><p><br /></p><p>Thanks[/QUOTE]</p><p><br /></p>

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