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<p>[QUOTE=&quot;Burton Strauss III, post: 2374820, member: 59677&quot;]Within the tollerance of your scale and of the Morgan&#039;s themselves... yes.</p><p><br /></p><p>Say your scale reads to 0.01g with an accuracy of 5%. This typically means that 95% of the time, the weight shown will be within 5% of the true weight (95% CI - confidence interval).</p><p><br /></p><p>For a Morgan $ - uncirculated, as it came from the mint (zero wear), is 26.730 grams with a tolerance of (+/-)0.097 grams. Or 26.633 to 26.827. Assuming the coin was within tollerance when issued (a decent chance, they did check samples).</p><p><br /></p><p>And for ease of calculation the Morgan in the slab weight 100g.</p><p><br /></p><p>So the slab + coin actually weighs between 95.00 and 105.00 grams.</p><p><br /></p><p>Subtracting the coin weight gives you the slab weight.</p><p><br /></p><p>95.00 - 26.827 = 68.173 but you lose the digit (limiting accuracy is the scale), so 68.17</p><p>105 - 26.633 = 78.367 or 78.37.</p><p><br /></p><p>So your slab weight is 73.27&nbsp; +/- 5.10g (for reference, a US Nickel weights 5g)</p><p><br /></p><p>In order to improve that accuracy, you need to measure 100s of examples of the same coin, same wear state and same slab+gasket, etc. The formulas to use are left as an exercise for a reader who has taken statistics more recently than I...</p><p><br /></p><p>Can it be done? Sure.[/QUOTE]</p><p><br /></p>

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