This is so mentalist, I love it. You guys know the Jelly-bean Jar Guessing Rule, right? The 'last' person who tallies & averages ALL THE OTHER GUESSES* is statistically most likely to win. *(discounting 'absurd outliers' : how on earth does someone guess ~4lbs avd or troy???) Online I see estimated new dime weights in this quantity between 8,278 (? pure Ag) > 9,172 grams total. Your total obviously 'less than' ; so too I adjust the underweights who factored (*.9) erroneously. If we estimate 2.5 gr per dime *50 *73 = 9,125 grams, but the adjusting voting average is 8,956 gr or almost 72 rolls! (Unless you're being clever, +1 roll is an error.) My Guess (for cheaters to beat) = your pure Ag horde weighs ~ 289 English Troy Ounces.
There will be 1 more hint at 7:30 Ps you are allowed 2 guesses if you want to reavaluate with the 2nd clue
Well that changes a lot. I calculated 73 rolls of dimes to = $8544.27 @ 32.36. I don't think I could make an accurate guess based on your 2 clues. I'll give it a shot though. I'll try 262 t.o and 312 t.o.
wow lol I cant believe we picked the same number kinda. I literally spend a minute thinking of a really random number before you posted so i dont overlap someones and look at what we got here.
Ya, this contest blows. When you specify "73 rolls" it's implicitly warranted not to be > +/-2. ASK @ USD$ 32.51 puts USD$ 10k ~310 t.o. > 341 t.o. You collect US coins, an American can't pretend its "10 grand" in something guess-y either... Erroneous hints mean you need to send all Guessers DMPL Morgans, Year of Our Choice LOL