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<p>[QUOTE=&quot;cmezner, post: 5143956, member: 87809&quot;]I am reviving this thread since I didn&#039;t get any answers to a question I asked in this thread:</p><p><a href="https://www.cointalk.com/threads/antioch-on-the-orontes.370411/" class="internalLink ProxyLink" data-proxy-href="https://www.cointalk.com/threads/antioch-on-the-orontes.370411/">https://www.cointalk.com/threads/antioch-on-the-orontes.370411/</a></p><p><br /></p><p>Maybe my question is silly? In this case, please say so.</p><p><br /></p><p>Anyway, Carl Wilmont said:</p><p><br /></p><blockquote><p><span style="color: #0000ff">Carl Wilmont said: ↑</span></p><p><span style="color: #0000ff">Augustus (27 BC – 14 AD). AR Tetradrachm (26mm, 15.10 g, 12h). Antioch mint, Seleucis Pieria, Syria. Dated year 29 of the Actian Era and Cos. XII = October-December 3 BC.</span></p></blockquote><p><br /></p><p>And my question was:</p><p><br /></p><p>trying to understand how the numismatists calculate the date, it is like a riddle - is the following reasoning correct?</p><p><br /></p><p>As K = 20, Θ = 9 it is the year 29 of the Actian Era. The Actian Era dates from the victory of Caesar over Antony at Actium in 31 BC. If the era started before the common era (BC or BCE), to determine the common era (AD or CE) date, subtract the era start year from the date on the coin.</p><p><br /></p><p>31 - 29 = 2 BC</p><p>Cos XII = 12th consulate Augustus became consul for the 12th time on January 1, 5BC</p><p><br /></p><p>do we subtract 2 BC from 5 BC: 5 - 2 = 3 BC to date the tetradrachm?</p><p><br /></p><p>Thanks in advance for your input<img src="styles/default/xenforo/clear.png" class="mceSmilieSprite mceSmilie1" alt=":)" unselectable="on" unselectable="on" />[/QUOTE]</p><p><br /></p>

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