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Required area = (area of large semicircle with radius 4.5 cm) <br> `-` (area of two smaller semicircle with radius of each `(3)/(2) cm` and a circle with radius `(4.5)/(2) cm`) `+` (area of smaller semicircle with radius `(3)/(2) cm`) <br> `= (1)/(2) pi (4.5)^(2) - [2 xx (1)/(2) pi ((3)/(2))^(2) + pi ((4.5)/(2))^(2)] + [(1)/(2)pi ((3)/(2))^(2)]` <br> `= (1)/(2) pi (4.5)^(2) - pi ((3)/(2))^(2) - pi ((4.5)/(2))^(2) + (1)/(2) pi ((3)/(2))^(2)` <br> `= (1)/(4) pi [2 xx (4.5)^(2) - 9 - (4.5)^(2) + (9)/(2)] = (1)/(4) pi xx 4.5 [2 xx 4.5 - 2 - 4.5 + 1]`<br> `= (1)/(4) pi xx 4.5 (3.5) = (1)/(4) xx (22)/(7) xx 4.5 xx 3.5 = 12.375 cm^(2)`Transcript

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00:00 - 00:59 | question is three semicircles each of diameter 3 cm a circle of diameter 4.7 m and a semicircle of radius 5 cm find the area of shaded portion is we have to find the area of the shaded portion here it is a circuit according to the question is this semicircle is remaining parties 3333 semicircles each in semicircle ABC has diameter 3 circle of diameter is diameter is 4.5 CM now I will |

01:00 - 01:59 | its diameter is 3 cm radius of a circle is 1.5 cm is a semicircle b b has also produced in it is because it's given 4.5 cm It means 4.5.2 I get to that radius of a circle of radius 4.5 which is that this |

02:00 - 02:59 | School circle distance and I can say is again its radius is 4.5 and this is all the data from the first area of big circle pictures India Circle now are is 4.5 it means I can write bye-bye to INR to 4.5 converting I have to add this one area of Semi circle |

03:00 - 03:59 | which is it is it is also means value of a beam is 1.5 X 21.5 it is 1.5 square and area of semicircle CCNA area will be exactly La CD Circle to 2.25 find the area of the |

04:00 - 04:59 | semi circle plus this credit card it can be written area we have to add the area of a + b and will exclude a and c and now we will put all the E + 1 upon 2 + b is 2.5 whole square + 3 + 1.5 whole it 1.25 taking common 541 |

05:00 - 05:59 | because it is the area of circle D it is a closet and I love you will torque calculation to get 1.254 254.254 51 again 2.2.52 5.1.2 buy into adding 22.50 |

06:00 - 06:59 | 1.25 in 2.5.0 625 solving between after cancel Appam to 11.25 after cancer light but point 255 it is -5.25 now I will be taking com 11.25 it means if we put value is 20 to solve it will be 8.93 |

07:00 - 07:59 | 12.5 CM of the shaded Pole is 12.3 75 |

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