I do own this bag Josh, but that's a rather long line you're standing in. Purchased from the survivor of a Virginia banker, this is one of my...
I would start first by asking the seller if he / she even knew the coin was fake. You wouldn't believe the number of fly-by-nighters who care...
MS65
How's this for a mint bag? [ATTACH]
VF30
This looks like a coin I used to own . . . I love stuff like this!
This was easily the nicest circ 1901 Morgan I've ever seen. Unfortunately, I was not able to capture the luster well at all, and the color in the...
Yeah, I don't like the 12 month limitation one bit . . . I've earned 2500+ feedbacks on eBay, and have a 100% rating, like so many others. Why...
I don't care to do business with anyone who considers it fair to take a free ride on someone else's advertising expenses to make sales. The...
Frankly, I think you both have some issues to correct. I don't leave sellers hanging if I won't be paying within 24 hours of auction's end. If...
I have recently bent the ear of the Minnesota Department of Commerce regarding the Minnesota Coin Dealer Law,...
edited - click link https://www.cointalk.com/threads/premiums-paid-for-collectible-coins-made-of-precious-metals.249502/#post-1957922
Taxes should play into your decision. When you sell the car, your basis cost must be established to determine your taxable gain. Would you like...
You may simply have happened across it before the dealer could assemble a complete submission package. I sometimes make an exceptional coin...
Yes, they do.
I understand the OP's sentiment, but it's important to leave the TPG's some latitude in helping the uninitiated to assign value if they refuse to...
If you are really considering doing something to these yourself, I emplore you to entrust the 1827 to either NGC or PCGS for conservation and...
Would you mind double-checking your measurement? A normal dime is smaller than that . . . 17.9mm, or 0.70 inches.
That's accounted for in my calculation of the estimated diameter of 13.4mm. 1.4 / 2.5 = [PI*(D/2)^2] / [PI*(17.9/2)^2] The PI and the 4 are in...
It's both . . . (PI)*R^2 = (PI)*(D/2)^2 I just provided the diameter instead of the radius because it is too difficult to measure the radius of a...
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