It would be interesting to see if acetone can even react on a toned copper coin or if it would have to be a relatively untoned coin to react.
I'll go FR02 for the Morgan and G04 for the Walker. While they are low grade, I think they look respectable for their grades.
Here's an article about a reaction that occurs when copper, oxygen, and acetone are exposed to light. The paper mentions that the reaction does...
Waaay out of my budget, but once you complete the set you'd better post it here so we can all see it!!
I'm guessing MS64. A very pretty coin, especially the reverse, but her cheek looks like she may have been in a knife fight...
My first thought was whizzed, so I'll join the whizzed group.
Not sure how much it'll sell for, but it'll definitely sell for enough money to prompt all of the local news outlets around to country to post...
That's the find of a lifetime. Congratulations!
Man, that's a good one! That's a pretty funny casualty of autocorrect. And maybe they cut a half dollar in half for that last 25¢?
I don't know about the other denominations, but in the Steve Tompkins bust quarter book, he estimates a 10% survival rate for 1796, 2-3% for...
Definitely a neat idea, and as you said a great way to own more coins by turning them over quicker. I'm still at the point in my coin collecting...
It appears to have sold, so here's the seller's pictures for posterity's sake in case someone comes across this thread five years from now....
That's an impressive stack of large cents! I've enjoyed lurking on this thread for the past few months and have found it quite interesting to...
Cool find! I was just literally reading about these the other day with the loop in the upright in the R. Quite the coincidence.
My serious grade would be G details, cleaned in scratched. My non-serious grade would be "had a rough life-70!"
If it were me and the X really bothered me I'd probably "fix" the marks by carrying it in my pocket and letting it wear down. Obviously this...
Haha, glad to see that everyone enjoyed my mathematical mess! I'm not sure about how to calculate it if the leads aren't directly across from each...
Out of boredom I decided to calculate a formula for resistance if you put the leads directly across from each other on the edge of the coin (e.g.-...
The units for resistivity are Ω*m, not Ω/m, and the units for the resulting resistance should be in Ω, not Ω/m^2.
I think I agree with you. Given length L=2.736 m, cross sectional area A=1x10^-6 m^2, and resistivity ρ=1.59x10^-8 Ω•m: R=ρL/A R=(1.59x10^-8...
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