Machine doubling is identified by the flat shelf like doubling and the reduced size of what's being doubled right??? "Trying to learn something new every day"
So it looks like by the graphics machine doubling does reduce the size of what's being doubled but when I read what was in Wexler's they didn't mention anything about a reduced size of what's being doubled. So I'm still confused is it reduced always or sometimes?
Machine doubling does not reduce the size of anything. The size remains the same. The doubling occurs on the same amount of space on the devices. "True" doubling or hub/die doubling increases the size of these devices.
Ok it just in your first graphic that shows machine doubling that the size of the L being doubled was smaller also I had thought that a couple of other members had mentioned in the past about machine doubling reduced the size but I'm old I don't always remember things as well as I use to. "Trying to learn something new every day to make up for what I've forgotten"
It takes time to learn these things. Be patient and keep at it. The day will come when you are correct.
Sorry for explaining it poorly. The doubling makes it look like the devices are smaller. The way I would best describe it is that if you drew an outline of the device of a machine doubled coin and one that is not doubled, the outlines should be the same. Only a hub/die doubling makes it larger. The raised portion will look like it shrank. I think that's what the photo means when it says "reduced" but that shelf-life look comes from the base of the device, which remains the same.
In the picture it looks like the machine doubling was made by part of the L being doubled getting flattened out reducing the original size of the L. On the hub doubling a second L was placed next to the original making it wider. So basically with machine doubling since it's not a redone die is causing the doubling by damaging the original to create the doubling right?