Hi All, I have been looking at a 1965 Austrian 10 Schilling coin on a website and I am considering to buy it. Here is my question to you all. The website has the specs on the coin and it says the following: SPECIFICATIONS Composition: Silver Weight(g): 7.5000g Weight(Oz): 0.24 Oz Fineness: 0.6400 Net Content: 0.15 Oz Diameter: 26.90mm I know this a silver coin but am I right to assume that the silver content is 64% silver at 7.5 grams ? Is the fineness term used here the same as the ASE which is 99.9% silver at 31.10 grams? All help is appreciated. Thanks John
I don't understand the "at 7.5 grams" portion of your question. Based on what you posted above: The coin weighs 7.5000 grams. The fineness is 0.6400 which means that 64.00% of the weight of that coin is silver. 7.5000 grams X 0.6400 = 4.8000 grams. So the silver content of the coin is 4.8000 grams. Converting 4.8000 grams to troy ounces we get 0.15432 troy ounces. So the 1965 Austrian 10 Schilling coin in your question contains 0.15432 troy ounces of silver. Again, I don't understand the "at 31.10 grams" portion of your question. An ASE has a fineness of 0.999 which means it is 99.9% silver and 0.1% something else. The 1965 Austrian 10 Schilling coin in your question is 64% silver. Standard US silver coins are 90% silver. ASEs are 99.9% silver.
