To the powers that be: The $10 gold AmericanGoldEagle is: .866 in diameter sells for $215 (Proof) .25 gold troz oz. 0.2727 troy oz. of gold. The $ 5 gold AmericanGoldEagle is: .65 in diameter sells for $105 (Proof) .10 gold troz oz. 0.1091 troy oz. of gold. The $ 5 San Franciso Commemorative: .85 in diameter sells for $230 (Proof) 8.359 grams 90% gold, 10% alloy So i'm not a gold person, but how do these three coins relate.. despite the difference in wording, why isn't the 2006 $5 Gold Proof San Francisco Mint Commemorative.. not a $10 Gold Proof in denomination it sounds much closer to that value? or is this merely the call of Congress.. and having something to do with Coin vs. Bullion?
I was thinking the exact same thing myself. I don't know why they make the commems' denomination $5 when they're nearly the same weight as the 1/4 oz eagle. As a matter of fact, I don't know why on Earth they don't make them the exact same purity, weight and denomination as the 1/4 oz Eagle. Why not make it 22K instead of 21.6K...makes no sense to me. :rolling:
The denomination really doesn't matter that much. The price of Gold goes up and down like a roller coaster.
Yes, but that's not really my point. The somewhat strange thing is that you have the U.S. Mint producing two gold coins at the same time that are nearly similar in many respects (close in weight <~1/4 oz>, gold content <.90 vs..9167>, etc.), but are just off slighty and they don't have the same denomination. Also, as we all know, the denomination on today's gold coins makes no difference whatsoever. There's no real problem with any of this. It's just kind of weird. Even though the denomination doesn't matter, one would logically think that two gold coins from the same time period that basically have the same dimensions would have the same denomination.
