No, and I will try to explain. If the die is not doubled, a letter on it will be struck once and the size will be the true size. If a die is doubled, since the doubling occurs when the die is struck the 2nd time, the first letter would have been true size, but when the second ( doubling) strike on it, the second letter will be full size, but the first letter will be diminished, BUT the total width of that area will be 'true size' 2nd strike + portion of first strike that wasn't overstruck by the 2nd strike. So the size of the doubled area will be larger than 'true size' but typically the same height. Look at the last photo in the series Look at the bottom of the "D" , notice how each separation is less in size. This is what we get with Machine doubling damage ( MDD) because there was only one strike on the working die ( rather than doubled), but there was physical interactions as the die struck and withdrew, moving enough metal to make the appearance of multiple strikes, but it was just shearing some of the metal in flat steps, but but when the images are added in height they total about or less than the normal area. If it was multiple struck working die ( doubled or tripled DD,TD), then the red area would be the size of a normal letter ( second hubbing) plus the size of the offset letter ( first hubbing). This is the extreme case of DDO, notice that each letter where they overlap make the total dimension greater rather than a lesser section, Also they are the same height, no smearing. The same holds true for lesser doubled dies, it just takes more observation to see. It is hard to describe dimensional examples. If you have some clay, baking dough, or play-do, and a cookie cutter, you can produce the effect. Jim
Also, consider this: If it takes a magnification of about 10 million to see anything, do you really think it is worth anything?
