It has 8 different numbers - 0-7 - not in order however... I thought it was cool, just wanted to know if this was special at all.
I like those notes. I only came across such a note once in circulation. By my math only 1 bill out of 226,800 has no digits repeating.
One man's ceiling is another man's floor.....the serial number would only interest me if was 01234567 or 76543210.
Ditto. I'd pass on it, serial number-wise. I've heard these called "scrambled ladders" which to me is a marketing gimmick.
It's definitely neat but not neat enough for me to pull the trigger on buying it. (Based solely upon the serial number)
Pass. I can't find any reason to pay any premium for such with an SN like this beyond what a common SN on the same Series note of the same quality/grade should be selling for. Likewise, unless you can see the rest of the note before buying it, pass on it.
I saw the rest of the note - and its in a PMG GEM 65 holder. I picked it up for $85 shipped, I thought the serial was interesting enough for me to pay a little premium on it. Thanks for all the input!
Check your math...it's actually 1 out of 55 bills! How to calculate that: Assume for simplicity that all serial numbers from 00000000 to 99999999 are actually used, so that there are 100,000,000 possible serial numbers. In order for a serial number to have no repeated digits, the first digit can be anything (10 choices); the second can be anything that doesn't match the first digit (9 choices); the third can be anything that doesn't match one of the first two (8 choices), and so on for the rest. Thus the number of such serials is 10x9x8x7x6x5x4x3, which comes to 1,814,400. So the fraction of all bills that have no repeated digits is 1,814,400/100,000,000 = .018144, and if you hit the reciprocal button on your calculator, you see that this is roughly one out of 55.
We use the formula n!/[(n-r)!r!] where n is 10 digits and r is 8 possible places. That's (10x9x8x7x6x5x4x3x2x1)/[(2x1)(8x7x6x5x4x3x2x1)] = 45. We were both wrong. But you were closer.
