My first contest!

Hey, guys! The worker who is measuring the cable is Polish and he wants to add the additional 6' in the middle because he is worried that the ends will be frayed.

Chris

 

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Is this the same guy that noticed that half the nails had the head on the wrong end, and concluded that they were for the other side of the house?

 

After re-reading the question, I think there was a possible uncertainty of needing +6' for each cable, or needing +6' for each end of each cable. I think the original wording suggests that only +6' per cable is necessary, meaning each anchor needs about an extra 3 feet. That is how I read it and answered it!

 

That sounds strangely like what I posted in post #20.

 

Do we REALLY need another cell phone tower?

 

No! That was Missy Spikancusabich. She only has three fingers left so they had to get a divorce.

Chris

 

Yes because in real life cutting and splicing would make the cable weaker then one continous run.



But back to the paint?

 

What about the paint?

Chris

 

I don't understand the question (I'm a 7th grader)

 

Have to agree. This math is generally not taught until 8th grade. So you most likely have never encountered it. But basically it is trying to find the length (which is unknown to you) + a certain amount of feet and figure the total length needed for an entire project. You are given two knowns (height and width) to enable you figure the length. Talk to one of your parents, they may be able to help you with this.

 

I sent in my private message!

 

Are we contracting this work out? I only ask because the contractors I've dealt with will need an extra 25% length to account for screwups!

 

No! Every single man on the construction crew was personally trained by Doug so there won't be any screw-ups.

Chris

 

Pm sent. Thank you for the fun contest!

 

Someone may have already mentioned this, but you do not have enough information to answer this question unless you provide:

1) The weight of the cable in pounds per foot
2) The tension of the cable.

The simplistic Pythagorean answer assumes no gravitational pull and/or no mass of the cable.

 

maybe the extra 6 ft accounts for that?

 

well, in refrence to wheather is geometry or trig, it's actually pre-algebra. took it last year. I would say the equationg butttt everyone would know how to solve this then

 

lol, stlouiscoin i did it my 7th grade year because i was in algebra. i'm in 9th grade and in trig, thinking of stepping up to calculus.

 

I get it now, this contest is meant to weed out the dummies like me, cause I didn't understand half of the replies posted in the thread. You all better be glad I ain't building the cell towers near your house. PM sent, thanks for the contest.

 

same here actually, and well it was either algebra or pre-algebra. switched mid-year so i forget which one. either way, simple theory that can easily get over complicated